A radioactive decay can form an isotope of th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the original nucleus be $ _{Z}^{A}X $.When an $ \alpha $-particle $( _{2}^{4}He )$ is emitted,the mass number decreases by $ 4 $ and the atomi

Vedclass · Accepted Answer

one $ \alpha $ and two $ \beta $

Vedclass · Answer

(B) Let the original nucleus be $ _{Z}^{A}X $.When an $ \alpha $-particle $( _{2}^{4}He )$ is emitted,the mass number decreases by $ 4 $ and the atomic number decreases by $ 2 $. The new nucleus is $ _{Z-2}^{A-4}Y $.When a $ \beta $-particle $( _{-1}^{0}e )$ is emitted,the atomic number increases by $ 1 $ and the mass number remains unchanged.If we emit one $ \alpha $ and two $ \beta $ particles:$1$. After $ \alpha $ emission: $ _{Z-2}^{A-4}Y $$2$. After first $ \beta $ emission: $ _{Z-1}^{A-4}Y' $$3$. After second $ \beta $ emission: $ _{Z}^{A-4}Y'' $Since the atomic number $ Z $ is the same as the original nucleus,it is an isotope of the original nucleus.

$A$ radioactive decay can form an isotope of the original nucleus with the emission of which particles?

Similar Questions

$A$ radioactive element ${}_{92}^{242}X$ emits two $\alpha$-particles,one electron,and two positrons. The product nucleus is represented by ${}_{P}^{234}Y$. The value of $P$ is $..................$

$A$ radioactive element ${ }_{92}^{242} X$ emits two $\alpha$ particles,one electron and two positrons. The product nucleus is represented by ${ }_{P}^{234} Y$. The value of $P$ is

If a heavy nucleus has an $N/Z$ ratio higher than that required for stability,then:

Which of the following cannot be emitted by radioactive substances during their decay?

Vedclass Test Series

Exam Paper Generator

Online Exam Module