A capacitor of capacitance 6 , mu F is charge | vedclass

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Question

(C) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 6 \, \mu F = 6 	imes 10^{-6} \, F$Potenti

Vedclass · Accepted Answer

$0.03$

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(C) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 6 \, \mu F = 6 	imes 10^{-6} \, F$Potential difference $V = 100 \, V$Substituting the values into the formula:$U = \frac{1}{2} 	imes (6 	imes 10^{-6}) 	imes (100)^2$$U = 3 	imes 10^{-6} 	imes 10,000$$U = 3 	imes 10^{-6} 	imes 10^4$$U = 3 	imes 10^{-2} \, J$$U = 0.03 \, J$Therefore,the energy stored in the capacitor is $0.03 \, J$.

$A$ capacitor of capacitance $6 \, \mu F$ is charged up to $100 \, V$. The energy stored in the capacitor is ........ $J$.

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