A capacitor is charged by using a battery which is then disconnected. A dielectric slab is introduced between the plates which results in
increase in the potential difference across the plates and reduction in stored energy but no change in the charge on the plates
decrease in the potential difference across the plates and reduction in the stored energy but no change in the charge on the plates
reduction of charge on the plates and increase of potential difference across the plates
increase in stored energy but no change in potential difference across the plates
The expression for the capacity of the capacitor formed by compound dielectric placed between the plates of a parallel plate capacitor as shown in figure, will be (area of plate $ = A$)
A parallel plate capacitor with plate separation $5$ $\mathrm{mm}$ is charged up by a battery. It is found that on introducing a dielectric sheet of thickness $2 \mathrm{~mm}$, while keeping the battery connections intact, the capacitor draws $25 \%$ more charge from the battery than before. The dielectric constant of the sheet is_____.
A parallel plate capacitor has a capacity $C$. The separation between the plates is doubled and a dielectric medium is introduced between the plates. If the capacity now becomes $2C$, the dielectric constant of the medium is
If a dielectric substance is introduced between the plates of a charged air-gap capacitor. The energy of the capacitor will
The plates of a parallel plate capacitor with no dielectric are connected to a voltage source. Now a dielectric of dielectric constant $K $ is inserted to fill the whole space between the plates with voltage source remaining connected to the capacitor.