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(B) According to Newton's law of cooling,the rate of change of temperature is proportional to the temperature difference between the body and its surr

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$t_1 < t_2$

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(B) According to Newton's law of cooling,the rate of change of temperature is proportional to the temperature difference between the body and its surroundings: $\frac{dT}{dt} = -k(T - T_s)$.This implies that the rate of heating (or cooling) is higher when the temperature difference between the object and the surroundings is larger.In the first case,the temperature range is $0^{\circ}C$ to $5^{\circ}C$. The average temperature is $2.5^{\circ}C$,so the average temperature difference is $25^{\circ}C - 2.5^{\circ}C = 22.5^{\circ}C$.In the second case,the temperature range is $10^{\circ}C$ to $15^{\circ}C$. The average temperature is $12.5^{\circ}C$,so the average temperature difference is $25^{\circ}C - 12.5^{\circ}C = 12.5^{\circ}C$.Since the temperature difference is larger in the first case,the rate of heat transfer is higher,meaning the time taken $t_1$ is less than the time taken $t_2$ $(t_1 < t_2)$.

$A$ can is taken out from a refrigerator at $0^{\circ}C$. The atmospheric temperature is $25^{\circ}C$. If $t_1$ is the time taken to heat from $0^{\circ}C$ to $5^{\circ}C$ and $t_2$ is the time taken to heat from $10^{\circ}C$ to $15^{\circ}C$,then:

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