A hot liquid kept in a beaker cools from 80,^ | vedclass

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Question

$\frac{	heta_{1}-	heta_{2}}{t}=-K\left(\frac{	heta_{1}+	heta_{2}}{2}-	heta_{0}ight)$

$t=2 \min =120 \mathrm{s}$

$\frac{80-70}{120}=-\math

Vedclass · Accepted Answer

$216$

Vedclass · Answer

$\frac{	heta_{1}-	heta_{2}}{t}=-K\left(\frac{	heta_{1}+	heta_{2}}{2}-	heta_{0}ight)$

$t=2 \min =120 \mathrm{s}$

$\frac{80-70}{120}=-\mathrm{K}\left(\frac{80+70}{2}-30ight)$   $...(i)$

$\frac{60-50}{t}=-K\left(\frac{60+50}{2}-30ight) \ldots(	ext { ii })$

$(i)$ $/(	ext { ii }) \Rightarrow(t=216 \mathrm{s})$

A hot liquid kept in a beaker cools from $80\,^oC$ to $70\,^oC$ in $2\, min$. If the surrounding temperature is $30\,^oC$, then the time of cooling of the same liquid from $60\,^oC$ to $50\,^oC$ ........ $\sec$

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