A bullet of mass 20, g travelling horizontall | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Mass of bullet $m=0.02 \mathrm{kg}$

Initial velocity of bullet $v_{1}=500 \mathrm{m} / \mathrm{s}$

Mass of block $M=10 \mathrm{kg}$

Initial v

Vedclass · Accepted Answer

$0.16$

Vedclass · Answer

Mass of bullet $m=0.02 \mathrm{kg}$

Initial velocity of bullet $v_{1}=500 \mathrm{m} / \mathrm{s}$

Mass of block $M=10 \mathrm{kg}$

Initial velocity $v_{2}=0$

Final velocity $v_{1}^{\prime}=100 \mathrm{m} / \mathrm{s}$

Now, the final velocity of block when bullet comes out

If block velocity $=v^{\prime}_{2}$

$m v_{1}+M v_{2}=m v_{1}+M v_{2}^{\prime}$

$0.02 	imes 500=0.02 	imes 100+10 v_{2}^{\prime}$

$v_{2}^{\prime}=\frac{10-2}{10}$

$v_{2}^{\prime}=0.8 \mathrm{m} / \mathrm{s}$

Now, after moving $0.2$ $\mathrm{m}$

Change in kinetic energy $=$ work done

$0-\frac{1}{2} 	imes 10 	imes(0.8)^{2}=-\mu 	imes 10 	imes 10 	imes 0.2$

$\mu=0.16$

Hence, the friction coefficient is $0.16$

Similar Questions

A hockey player is moving northward and suddenly turns westward with the same speed to avoid an oopponent. The force that acts on the player is

A block of mass $70\,kg$ is kept on a rough horizontal surface $(\mu = 0.4)$. A person is trying to pull the block by applying a horizontal force, but the block is not moving. The net contact force exerted by the surface on the block is $F$, then

Meena applies the front brakes, while riding on her bicycle along a flat road. The force that slows her bicycle is provided by the

A conveyor belt is moving at a constant speed of $2\, ms^{-1}$. A box is gently dropped on it. The coefficient of friction between them is $\mu = 0.5$. The distance that the box will move relative to belt before coming to rest on it, (taking $g = 10\, ms^{-2}$) is ........ $m$.