(A) When the switch is closed,the circuit is connected to a $90\, V$ $DC$ battery.An ideal inductor has zero resistance,so it acts as a short circuit

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(A) When the switch is closed,the circuit is connected to a $90\, V$ $DC$ battery.An ideal inductor has zero resistance,so it acts as a short circuit for $DC$ current.Since the bulb and the inductor are connected in parallel,the entire current from the battery will flow through the path of least resistance,which is the ideal inductor.Consequently,no current flows through the bulb,and it does not glow.

Class 12 Physics Electromagnetic Induction R-L D.C. Circuit

Easy

$A$ bulb of $100\, W$ is connected in parallel with an ideal inductance of $1\, H$. This arrangement is connected to a $90\, V$ battery through a switch. On pressing the switch,the

A
bulb does not glow
B
bulb glows
C
bulb glows after a short time and then continues to glow
D
bulb glows for a short time and then stops glowing

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R-L D.C. Circuit

In the circuit shown below,the key $K$ is closed at $t = 0$. The current through the battery is

Medium

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An inductor coil stores $64 \, J$ of magnetic field energy and dissipates energy at the rate of $640 \, W$ when a current of $8 \, A$ is passed through it. If this coil is joined across an ideal battery,find the time constant of the circuit in seconds.

DifficultJEE MAIN 2021

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$A$ coil of self-inductance $10\,mH$ and resistance $0.1\,\Omega$ is connected through a switch to a battery of internal resistance $0.9\,\Omega$. After the switch is closed,the time taken for the current to attain $80\%$ of its saturation value is: [take $ln\,5 = 1.6$] (in $,s$)

DifficultJEE MAIN 2019

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In the figure,a lamp $P$ is in series with an iron-core inductor $L$. When the switch $S$ is closed,the brightness of the lamp rises relatively slowly to its full brightness compared to the case without the inductor. This is due to:

Medium

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Regarding the given circuit,the correct statement is:

MediumAP EAMCET 2023

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$A$ bulb of $100\, W$ is connected in parallel with an ideal inductance of $1\, H$. This arrangement is connected to a $90\, V$ battery through a switch. On pressing the switch,the

Similar Questions

In the circuit shown below,the key $K$ is closed at $t = 0$. The current through the battery is

An inductor coil stores $64 \, J$ of magnetic field energy and dissipates energy at the rate of $640 \, W$ when a current of $8 \, A$ is passed through it. If this coil is joined across an ideal battery,find the time constant of the circuit in seconds.

$A$ coil of self-inductance $10\,mH$ and resistance $0.1\,\Omega$ is connected through a switch to a battery of internal resistance $0.9\,\Omega$. After the switch is closed,the time taken for the current to attain $80\%$ of its saturation value is: [take $ln\,5 = 1.6$] (in $,s$)

In the figure,a lamp $P$ is in series with an iron-core inductor $L$. When the switch $S$ is closed,the brightness of the lamp rises relatively slowly to its full brightness compared to the case without the inductor. This is due to:

Regarding the given circuit,the correct statement is:

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