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Question

Energy stored in capacitor

$=\frac{1}{2} \mathrm{CV}^{2}=\frac{1}{2} 	imes 5 	imes 10^{-6} 	imes(200)^{2}=10^{-1} \mathrm{\,J}$

The fraction

Vedclass · Accepted Answer

$2/32\,J$

Vedclass · Answer

Energy stored in capacitor

$=\frac{1}{2} \mathrm{CV}^{2}=\frac{1}{2} 	imes 5 	imes 10^{-6} 	imes(200)^{2}=10^{-1} \mathrm{\,J}$

The fraction lost in $500\, \Omega$ is $\frac{5}{8}$ of total so

$\mathrm{H}=\frac{5}{8} 	imes \frac{1}{10}=\frac{1}{16} \mathrm{\,J}=\frac{2}{32} \mathrm{\,J}$

A capacitor of capacitance $5\,\mu F$ is connected to a source of constant $emf$ of $200\,V$ for a long time, then the switch was shifted to contact $2$ from contact $1$ . The total amount of heat generated in the $500\,\Omega $ resistance, thereafter is

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