$A$ bulb is connected first with $DC$ and then $AC$ of the same voltage. In which case will it shine more brightly?

An $AC$ voltmeter connected between points $A$ and $B$ in the circuit below reads $36 \,V$. If it is connected between $A$ and $C$,the reading is $39 \,V$. The reading when it is connected between $B$ and $D$ is $25 \,V$. What is the reading when it is connected between $A$ and $D$? (Assume that the voltmeter reads true $rms$ voltage values and that the source generates a pure $AC$.)

If $C, R, L$ and $I$ denote capacity,resistance,inductance and electric current respectively,the quantities having the same dimensions of time are :
$(1)$ $C R$
$(2)$ $\frac{L}{R}$
$(3)$ $\sqrt{L C}$
$(4)$ $L I^2$

Assertion: Long distance power transmission is done at high voltage.
Reason: At high voltage supply, power losses are less.

Assertion : In the purely resistive element of a series $LCR$ $AC$ circuit,the maximum value of $rms$ current increases with an increase in the angular frequency of the applied $e.m.f$.
Reason : $I_{\max} = \frac{\varepsilon_{\max}}{Z}$,where $Z = \sqrt{R^2 + (\omega L - \frac{1}{\omega C})^2}$ and $I_{\max}$ is the peak current in a cycle.