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(D) For a convex mirror,the magnification $m$ is given by $m = \frac{f}{f-u}$. Since for a real object,$u$ is negative (let $u = -|u|$),the magnificat

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for no value of $u$

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(D) For a convex mirror,the magnification $m$ is given by $m = \frac{f}{f-u}$. Since for a real object,$u$ is negative (let $u = -|u|$),the magnification becomes $m = \frac{f}{f+|u|}$. Because $f$ and $|u|$ are positive,the denominator $(f+|u|)$ is always greater than the numerator $f$. Therefore,the magnification $m$ is always less than $1$ $(m < 1)$. This implies that a convex mirror always forms a diminished image of a real object. Thus,it can never form an image larger than the object.

The image formed by a convex mirror of a real object is larger than the object:

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