A box contains 4 white pens and 2 black pens. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Total number of pens in the first box = $4 + 2 = 6$.Total number of pens in the second box = $3 + 5 = 8$.The probability of selecting a white pen

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(C) Total number of pens in the first box = $4 + 2 = 6$.Total number of pens in the second box = $3 + 5 = 8$.The probability of selecting a white pen from the first box = $\frac{4}{6} = \frac{2}{3}$.The probability of selecting a white pen from the second box = $\frac{3}{8}$.Since the selection from each box is an independent event,the probability that both pens are white is the product of their individual probabilities.Required probability = $\frac{2}{3} 	imes \frac{3}{8} = \frac{6}{24} = \frac{1}{4}$.

$A$ box contains $4$ white pens and $2$ black pens. Another box contains $3$ white pens and $5$ black pens. If one pen is selected from each box,then the probability that both the pens are white is equal to

Similar Questions

$A$ number is chosen at random from the first ten natural numbers. The probability that the number is odd and a perfect square is

$A$ committee of $5$ members is to be formed from $6$ men and $4$ women. The probability that at least one woman is present in the committee is

$A$ bag contains $5$ black balls, $4$ white balls, and $3$ red balls. If a ball is selected at random, the probability that it is a black or red ball is

$2$ dice are thrown. Find the odds in favour of getting the sum $5$.

Three $6$-faced dice are thrown together. The probability that no two dice show the same number on them is

Vedclass Test Series

Exam Paper Generator

Online Exam Module