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(B) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event of getting a sum of $5$.The favorable out

Vedclass · Accepted Answer

$1:8$

Vedclass · Answer

(B) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event of getting a sum of $5$.The favorable outcomes are $(1, 4), (4, 1), (2, 3), (3, 2)$.Number of favorable outcomes $n(A) = 4$.Number of unfavorable outcomes = Total outcomes - Favorable outcomes = $36 - 4 = 32$.The odds in favour of an event are defined as the ratio of the number of favorable outcomes to the number of unfavorable outcomes.$	herefore 	ext{Odds in favour of sum } 5 = \frac{n(A)}{n(A^c)} = \frac{4}{32} = \frac{1}{8}$ or $1:8$.

$2$ dice are thrown. Find the odds in favour of getting the sum $5$.

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