A body travels uniformly a distance of (13.8 | vedclass

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(C) Velocity $v$ is given by $v = \frac{d}{t}$.For division,the relative error is the sum of the relative errors of the individual quantities: $\frac{

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$8.95$

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(C) Velocity $v$ is given by $v = \frac{d}{t}$.For division,the relative error is the sum of the relative errors of the individual quantities: $\frac{\Delta v}{v} = \frac{\Delta d}{d} + \frac{\Delta t}{t}$.Percentage error in velocity $= \left( \frac{\Delta d}{d} 	imes 100 ight) + \left( \frac{\Delta t}{t} 	imes 100 ight)$.Substituting the given values: $\left( \frac{0.2}{13.8} 	imes 100 ight) + \left( \frac{0.3}{4.0} 	imes 100 ight)$.$= 1.449 + 7.5 = 8.949 \% \approx 8.95 \%$.

$A$ body travels uniformly a distance of $(13.8 \pm 0.2) \ m$ in a time $(4.0 \pm 0.3) \ s$. The percentage error in velocity is ......... $\%$

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