A body of mass 1,kg is thrown upwards with a | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,Initial\,velocity\,u = 20m/s;\
m = 1\,kg\,Kinetic\,energy\, = {m{maximum}}\
potential\,energy\,\
Initia

Vedclass · Accepted Answer

$20$

Vedclass · Answer

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,Initial\,velocity\,u = 20m/s;\
m = 1\,kg\,Kinetic\,energy\, = {m{maximum}}\
potential\,energy\,\
Initial\,kinetic\,energy\, = \frac{1}{2} 	imes 1 	imes {20^2}\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 200\,J\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Mgh\,(\max ) = 200\,J.
\end{array}$

$\begin{array}{l}
	herefore \,\,\,h = 20\,m.\
The\,height\,travelled\,by\,the\,body,\
h' = 18\,m\
	herefore \,Loss\,of\,energy\,due\,to\,air\,friction\
 = mgh - mgh'\
 \Rightarrow \,Energy\,lost\, = 200\,J - 1 	imes 10 	imes 18\,J\,\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 20\,J.
\end{array}$

A body of mass $1\,kg$ is thrown upwards with a velocity $20\, m/s.$ It momentarily comes to rest after attaining a height of $18\, m.$ How much energy is lost due to air friction ? ........... $\mathrm{J}$ $ (g = 10 \,m/s^2)$

Similar Questions

A $1000\,\, kg$ elevator rises from rest in the basement to the fourth floor, a distance of $20\,\, m$. As it passes the fourth floor its speed is $4\,m/sec$. There is a constant frictional force of $500\, N$. The work done by the lifting mechanism is

The graph between the resistive force $ F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25\, kg$ and initial velocity is $2\, m/s$. When the distance covered by the body is $4m$, its kinetic energy would be .............. $\mathrm{J}$

A particle which is experiencing a force, given by $\vec F = 3\vec i -12\vec j$, undergoes a displacement of $\vec d = 4\vec i$ . If the particle had a kinetic energy of $3\, J$ at the beginning of the displacement, what is its kinetic energy at the end of the displacement?

A particle is released from height $\mathrm{S}$ from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of earth and the speed of the particle at that instant are respectively :

A time dependent force $F = 6t$ acts on a particle of mass $1\ kg$. If the particle starts from rest, the work done by the force during the first $1$ secand will be ............... $\mathrm{J}$