A body of mass $5\,kg$ rests on a rough horizontal surface of coefficient of friction $0.2.$ The body is pulled through a distance of $10\,m$ by a horizontal force of $25\, N$. The kinetic energy acquired by it is ......... $J$
$330$
$150$
$100$
$50$
KE acquired by a mass $m$ in travelling a certain distance $d$, starting from rest, under the action of a constant force $F$ is ..........
By what reasons chemical energy produced in chemical process ?
A block of mass $m=1\; kg$. moving on a horizontal surface with speed $v_{t}=2 \;m s ^{-1}$ enters a rough patch ranging from $x=0.10\; m$ to $x=2.01\; m .$ The retarding force $F$ on the block in this range is inversely proportional to $x$ over this range,
$F_{r}=\frac{-k}{x}$ for $0.1 < x < 2.01 \;m$
$=0$ for $x < 0.1\; m$ and $x > 2.01\; m$
where $k=0.5\; J .$ What is the final kinetic energy and speed $v_{f}$ of the block as it crosses this patch ?
An adult weighting $600\,N$ raises the centre of gravity of his body by $0.25\,m$ while taking each step of $1\,m$ length in jogging. If he jogs for $6\,km$, calculate the energy utilised by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting $10\,\%$ of energy intake in the form of food, calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.
Figure shows the variation of a force $F$ acting on a particle along $x$-axis. If the particle begins at rest at $x=0$, what is the particle's coordinate when it again has zero speed?