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(C) $1$. Distance is the total path length covered by the body. For three-quarters of a circle, the distance is $\frac{3}{4}$ of the circumference $(2

Vedclass · Accepted Answer

displacement $= \sqrt{2}r$, distance $= \frac{3\pi r}{2}$

Vedclass · Answer

(C) $1$. Distance is the total path length covered by the body. For three-quarters of a circle, the distance is $\frac{3}{4}$ of the circumference $(2\pi r)$.Distance $= \frac{3}{4} 	imes 2\pi r = \frac{3\pi r}{2}$.$2$. Displacement is the shortest straight-line distance between the initial and final positions. If the body starts at point $A$ and moves three-quarters of the circle to point $B$, the angle subtended at the center is $270^{\circ}$ (or $-90^{\circ}$).$3$. The initial position vector is $(r, 0)$ and the final position vector is $(0, -r)$.The displacement magnitude is the hypotenuse of a right-angled triangle with sides $r$ and $r$.Displacement $= \sqrt{r^2 + r^2} = \sqrt{2r^2} = \sqrt{2}r$.

$A$ body moves on three quarters of a circle of radius $r$. The displacement and distance The displacement and distance travelled by it are:

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