A scooter starts from rest moves in a straight line with a constant acceleration and covers a distance of $64 \,m$ in $4 \,s$
$(i)$ Calculate its acceleration and its final velocity.
$(ii)$ At what time the scooter had covered half the total distance ?
$(i)$ $a=? ; u=0 ; S =64 m ; t=4 s$
Using the equation $S=u t+1 / 2 a t^{2},$ we have
$64=0+a(4)^{2}$
or $a=4 m s ^{-2}$
Using the equation $v=u+\mu t,$ we have
$v=0+4 \times 4=16 m s ^{-1}$
$(ii)$ Given $S=32 m , t=?, d=4 m s ^{-2}$
Using the equation $S=u t+\frac{1}{2} a t^{2}$
$32=0^{\prime}+4 \times(t)^{2}$ or $t=2.82 s$
A body is thrown vertically upward with velocity $u$, the greatest height $h$ to which it will rise is,
In your everyday life, you come across a range of motions in which
$(a)$ acceleration is in the direction of motion.
$(b)$ acceleration is against the direction of motion.
$(c)$ acceleration is uniform.
$(d)$ acceleration is non$-$uniform.
Can you identify one example each of the above type of motion ?
Two cars $A$ and $B$ have their displacement$-$time graph as given below. Which car has a greater velocity ?
The velocity$-$time graph of a body has a negative slope. The body is undergoing
Distinguish between terms distance and displacement.