A block whose mass is $1 \;kg$ is fastened to a spring. The spring has a spring constant of $50\; N m ^{-1}$. The block is pulled to a distance $x=10\; cm$ from its equilibrlum position at $x=0$ on a frictionless surface from rest at $t=0 .$ Calculate the kinetic, potentlal and total energles of the block when it is $5 \;cm$ away from the mean position.
The block executes $SHM$, its angular frequency, as given
$\omega =\sqrt{\frac{k}{m}}$
$=\sqrt{\frac{50\, N m ^{-1}}{1 \,kg }}$
$=7.07 \,rad\, s ^{-1}$
Its displacement at any time t is then given by,
$x(t)=0.1\, \cos (7.07\, t)$
Therefore, when the particle is $5\; cm$ away from the mean position, we have
$0.05=0.1 \,\cos\, (7.07\, t)$
$\cos (7.07\, t)=0.5$ and hence
$\sin (7.07 \,t)=\frac{\sqrt{3}}{2}=0.866$
Then, the velocity of the block at $x=5 \,cm$ is
$=0.1 \times 7.07 \times 0.866 \,m s ^{-1}$
$=0.61\, m s ^{-1}$
Hence the $K.E.$ of the block.
$=\frac{1}{2} m v^{2}$
$=1 / 2\left[1\, kg \times\left(0.6123 \,m s ^{-1}\right)^{2}\right]$
$=0.19 \,J$
The $P.E$. of the block,
$=\frac{1}{2} k x^{2}$
$=1 / 2\left(50 \,N m ^{-1} \times 0.05\, m \times 0.05\, m \right)$
$=0.0625 \,J$
The total energy of the block at $x=5\, cm$
$= K.E. + P.E.$
$=0.25 \;J$
we also know that at maximum displacement. $K.E.$ is zero and hence the total energy of the system is equal to the $P.E.$ Therefore, the total energy of the system.
$=1 / 2\left(50 \,N m ^{-1} \times 0.1 \,m \times 0.1 \,m \right)$
$=0.25 J$
which is same as the sum of the two energies at a displacement of $5\; cm$. This is in conformity with the principle of conservation of energy
A mass $M$, attached to a horizontal spring, executes S.H.M. with amplitude $A_1$. When the mass $M$ passes through its mean position then a smaller mass $m$ is placed over it and both of them move together with amplitude $A_2$. The ratio of $\frac{{{A_1}}}{{{A_2}}}$ is
Two masses $m_1$ and $m_2$ connected by a spring of spring constant $k$ rest on a frictionless surface. If the masses are pulled apart and let go, the time period of oscillation is
A $5\; kg$ collar is attached to a spring of spring constant $500\;N m ^{-1} .$ It slides without friction over a hortzontal rod. The collar is displaced from its equilibrium position by $10.0\; cm$ and released. Calculate
$(a)$ the period of oscillation.
$(b)$ the maximum speed and
$(c)$ maximum acceleration of the collar.
Is the following Statement True or False ?
$1.$ If the spring is cut in two equal piece the spring constant of every piece decreases.
$2.$ Displacement of $SHO$ increases, its acceleration decrease.
$3.$ A system can happen to oscillate, have more than one natural frequency.
$4.$ The periodic time of $SHM$ depend on amplitude or energy or phase constant.
Two springs have spring constants ${K_A}$ and ${K_B}$ and ${K_A} > {K_B}$. The work required to stretch them by same extension will be