A ball is dropped and its displacement versus time graph is as shown (Displacement $x$ from ground and all quantities are positive upwards).

$(a)$ Plot qualitatively velocity versus time graph.

$(b)$ Plot qualitatively acceleration versus time graph.

884-175

Vedclass pdf generator app on play store
Vedclass iOS app on app store

It is clear from the graph that displacement $x$ is positive during motion. Ball is dropped from a height and its velocity increases in downward direction due to gravity field. In this condition $v$ is negative but acceleration of the ball is equal to acceleration due to gravity i.e., $a=-g$. When ball rebounds in upward direction its velocity is positive but acceleration is $a=-\mathrm{g}$. $(a)$ The velocity-time graph of the ball is shown in fig. $(i)$.

$(b)$ The acceleration-time graph of the ball is shown in fig. $(ii)$.

884-s175

Similar Questions

A particle moves along a straight line such that its displacement at any time $t$ is given by $s = (t^3 -3t^2 + 2)\,m$ The displacement when the acceleration becomes zero is........$m$

The velocity of a body depends on time according to the equation $v = 20 + 0.1{t^2}$. The body is undergoing

The velocity-displacement graph describing the motion of a bicycle is shown in the figure.

The acceleration-displacement graph of the bicycle's motion is best described by

  • [JEE MAIN 2021]

The accompanying graph of position $x$ versus time $t$ represents the motion of a particle. If $p$ and $q$ are both positive constants, the expression that best describes the acceleration $a$ of the particle is

  • [KVPY 2013]

The displacement of a particle, moving in a straight line, is given by $s = 2{t^2} + 2t + 4$ where $s$ is in metres and $t$ in seconds. The acceleration of the particle is........$ms^{-2}$