For a common base circuit,if $\frac{I_C}{I_E} = 0.98$,then the current gain for a common emitter circuit will be:

The collector supply voltage is $6 \text{ V}$ and a voltage drop across a resistor of $600 \Omega$ in the collector circuit is $0.6 \text{ V}$,in a circuit of a transistor connected in common emitter mode. If the current gain is $20$,then the base current is: (in $\text{ mA}$)

Given below are two statements:
Statement $I :$ $PN$ junction diodes can be used to function as a transistor,simply by connecting two diodes back-to-back,which acts as the base terminal.
Statement $II :$ In the study of transistors,the amplification factor $\beta$ indicates the ratio of the collector current to the base current.
In the light of the above statements,choose the correct answer from the options given below:

The current amplification factor of a transistor is $50$. In a $CE$ amplifier circuit, the collector resistance is $5 \, k\Omega$ and the input resistance is $1 \, k\Omega$. If the input voltage is $0.01 \, V$, the output voltage is ........ $V$.

In an $NPN$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$ and $2\%$ of the electrons recombine with holes in the base. The current gains $\alpha$ and $\beta$ are respectively:

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.