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(C) Step $1$: Time taken to reach the middle point of the train.Distance to cover $= 150 \, m = 0.15 \, km$.Relative speed $= 70 - 45 = 25 \, km/hr$.T

Vedclass · Accepted Answer

$2.37$

Vedclass · Answer

(C) Step $1$: Time taken to reach the middle point of the train.Distance to cover $= 150 \, m = 0.15 \, km$.Relative speed $= 70 - 45 = 25 \, km/hr$.Time $t_1 = \frac{0.15}{25} \, hr = 0.006 \, hr$.Distance covered by the motorbike in $t_1 = 70 	imes 0.006 = 0.42 \, km = 420 \, m$.Step $2$: Time taken to cover the remaining half of the train.Remaining distance to cover $= 150 \, m = 0.15 \, km$.New relative speed $= 65 - 60 = 5 \, km/hr$.Time $t_2 = \frac{0.15}{5} \, hr = 0.03 \, hr$.Distance covered by the motorbike in $t_2 = 65 	imes 0.03 = 1.95 \, km = 1950 \, m$.Step $3$: Total distance covered by the motorbike.Total distance $= 0.42 + 1.95 = 2.37 \, km$.

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