A car covers four successive 7 , km distances | vedclass

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(B) Let the distance for each segment be $d = 7 \, km$. Since the distances are equal,we use the harmonic mean formula for average speed.Let the speed

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$20$

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(B) Let the distance for each segment be $d = 7 \, km$. Since the distances are equal,we use the harmonic mean formula for average speed.Let the speeds be $v_1 = 10 \, km/h$,$v_2 = 20 \, km/h$,$v_3 = 30 \, km/h$,and $v_4 = 60 \, km/h$.The formula for average speed when distances are equal is $V_{avg} = \frac{n}{\frac{1}{v_1} + \frac{1}{v_2} + \frac{1}{v_3} + \frac{1}{v_4}}$,where $n = 4$.$V_{avg} = \frac{4}{\frac{1}{10} + \frac{1}{20} + \frac{1}{30} + \frac{1}{60}}$Find the common denominator for the fractions: $60$.$V_{avg} = \frac{4}{\frac{6+3+2+1}{60}} = \frac{4}{\frac{12}{60}} = \frac{4}{\frac{1}{5}}$$V_{avg} = 4 	imes 5 = 20 \, km/h$.

$A$ car covers four successive $7 \, km$ distances at speeds of $10 \, km/h$,$20 \, km/h$,$30 \, km/h$,and $60 \, km/h$ respectively. Its average speed over this total distance is (in $km/h$):

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