A thin rod of mass M and length L is struck a | vedclass

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(C) The angular momentum of the system about the midpoint $A$ is conserved during the collision because there are no external torques acting on the sy

Vedclass · Accepted Answer

$\frac{{mvL}}{2}$

Vedclass · Answer

(C) The angular momentum of the system about the midpoint $A$ is conserved during the collision because there are no external torques acting on the system about point $A$.Before the collision,the rod is at rest,so its angular momentum is zero.The angular momentum of the clay ball of mass $m$ moving with speed $v$ at a distance $L/2$ from the midpoint $A$ is given by $L = r 	imes p = (L/2) 	imes (mv) = \frac{mvL}{2}$.Since the external torque about $A$ is zero,the angular momentum of the system remains constant.Therefore,the angular momentum of the clay-rod system about $A$ after the collision is equal to the angular momentum of the clay ball before the collision,which is $\frac{mvL}{2}$.

$A$ thin rod of mass $M$ and length $L$ is struck at one end by a ball of clay of mass $m$,moving with speed $v$ as shown in the figure. The ball sticks to the rod. After the collision,the angular momentum of the clay-rod system about $A$,the midpoint of the rod,is:

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