A particle with position vector overrightarro | vedclass

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Question

(B) The angular momentum of a particle is defined by the cross product of its position vector and linear momentum: $\overrightarrow{L} = \overrightarr

Vedclass · Accepted Answer

$\overrightarrow{L}$ is maximum when $\overrightarrow{p}$ is perpendicular to $\overrightarrow{r}$

Vedclass · Answer

(B) The angular momentum of a particle is defined by the cross product of its position vector and linear momentum: $\overrightarrow{L} = \overrightarrow{r} 	imes \overrightarrow{p}$.By the properties of the cross product,the vector $\overrightarrow{L}$ is perpendicular to both $\overrightarrow{r}$ and $\overrightarrow{p}$.The magnitude of the angular momentum is given by $L = rp \sin 	heta$,where $	heta$ is the angle between $\overrightarrow{r}$ and $\overrightarrow{p}$.For the magnitude $L$ to be maximum,$\sin 	heta$ must be maximum,which occurs when $	heta = 90^{\circ}$.Therefore,$\overrightarrow{L}$ is maximum when $\overrightarrow{p}$ is perpendicular to $\overrightarrow{r}$.

$A$ particle with position vector $\overrightarrow{r}$ has a linear momentum $\overrightarrow{p}$. Which one of the following statements is true in respect of its angular momentum $\overrightarrow{L}$ about the origin?

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