જો ${x^{x\sqrt[3]{x}}} = {(x \cdot \sqrt[3]{x})^x}$ હોય,તો $x =$

  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $64/27$

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જો ${\left( \frac{2}{3} \right)^{x + 2}} = {\left( \frac{3}{2} \right)^{2 - 2x}}$ હોય,તો $x =$

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