$\frac{3\sqrt{2}}{\sqrt{6} + \sqrt{3}} - \frac{4\sqrt{3}}{\sqrt{6} + \sqrt{2}} + \frac{\sqrt{6}}{\sqrt{3} + \sqrt{2}} = $

  • A
    $5\sqrt{2}$
  • B
    $3\sqrt{2}$
  • C
    $2\sqrt{3}$
  • D
    $0$

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