E, m, l and G denote energy,mass,angular mome | vedclass

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(A) The dimensional formulas for the given quantities are:$[E] = [ML^2T^{-2}]$$[m] = [M]$$[l] = [ML^2T^{-1}]$$[G] = [M^{-1}L^3T^{-2}]$Substituting the

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(A) The dimensional formulas for the given quantities are:$[E] = [ML^2T^{-2}]$$[m] = [M]$$[l] = [ML^2T^{-1}]$$[G] = [M^{-1}L^3T^{-2}]$Substituting these dimensions into the expression $\frac{El^2}{m^5G^2}$:$\frac{[ML^2T^{-2}] \cdot [ML^2T^{-1}]^2}{[M]^5 \cdot [M^{-1}L^3T^{-2}]^2} = \frac{[ML^2T^{-2}] \cdot [M^2L^4T^{-2}]}{[M^5] \cdot [M^{-2}L^6T^{-4}]} = \frac{[M^3L^6T^{-4}]}{[M^3L^6T^{-4}]} = [M^0L^0T^0]$Since the dimensions are $[M^0L^0T^0]$,the quantity is dimensionless. Among the given options,an angle is a dimensionless quantity.

$E, m, l$ and $G$ denote energy,mass,angular momentum,and gravitational constant respectively. Then the dimensions of $\frac{El^2}{m^5G^2}$ are:

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