(C) The binding energy $B$ of a nucleus is defined as the energy equivalent of the mass defect $\Delta m$. The mass defect is given by $\Delta m = (Z

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$M(N, Z) = N M_n + Z M_p - B / c^2$

(C) The binding energy $B$ of a nucleus is defined as the energy equivalent of the mass defect $\Delta m$. The mass defect is given by $\Delta m = (Z M_p + N M_n) - M(N, Z)$. According to Einstein's mass-energy equivalence relation,$B = \Delta m c^2$. Substituting the expression for $\Delta m$,we get $B = [Z M_p + N M_n - M(N, Z)] c^2$. Rearranging the terms to solve for $M(N, Z)$: $B / c^2 = Z M_p + N M_n - M(N, Z)$ $M(N, Z) = Z M_p + N M_n - B / c^2$.

Class 12 Physics Nuclei Mass-Energy, Nuclear Binding Energy, Nuclear Stability

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$M_p$ denotes the mass of a proton and $M_n$ that of a neutron. $A$ given nucleus,of binding energy $B$,contains $Z$ protons and $N$ neutrons. The mass $M(N, Z)$ of the nucleus is given by ($c$ is the velocity of light):

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A
$M(N, Z) = N M_n + Z M_p - B c^2$
B
$M(N, Z) = N M_n + Z M_p + B c^2$
C
$M(N, Z) = N M_n + Z M_p - B / c^2$
D
$M(N, Z) = N M_n + Z M_p + B / c^2$

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Mass-Energy, Nuclear Binding Energy, Nuclear Stability

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$M_p$ denotes the mass of a proton and $M_n$ that of a neutron. $A$ given nucleus,of binding energy $B$,contains $Z$ protons and $N$ neutrons. The mass $M(N, Z)$ of the nucleus is given by ($c$ is the velocity of light):

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What is the fundamental reason for the chemical energy produced in a chemical process?

If an electron and a positron annihilate,the energy released is ........

If the binding energy per nucleon in $Li^7$ and $He^4$ nuclei are respectively $5.60 \ MeV$ and $7.06 \ MeV$, then the energy of the reaction $Li^7 + p \to 2He^4$ is ......... $MeV$.

Binding energy per nucleon of a fixed nucleus $X^A$ is $8 \ MeV$. It absorbs a neutron moving with kinetic energy $2 \ MeV$ and converts into $Y$,emitting two photons of energy $1 \ MeV$ and $4 \ MeV$ respectively one after the other. The binding energy per nucleon of $Y$ (in $MeV$) is:

If the binding energy per nucleon of a nuclide is high,then:

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