If the radius of a nucleus with atomic number | vedclass

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(B) The electric potential $V$ at the surface of a charged sphere (nucleus) is given by the formula: $V = \frac{1}{4\pi\epsilon_0} \cdot \frac{Q}{r}$

Vedclass · Accepted Answer

$8 	imes 10^6 \ V$

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(B) The electric potential $V$ at the surface of a charged sphere (nucleus) is given by the formula: $V = \frac{1}{4\pi\epsilon_0} \cdot \frac{Q}{r}$ Where $Q = Ze$ is the total charge of the nucleus. Given: $Z = 50$ $e = 1.6 	imes 10^{-19} \ C$ $r = 9 	imes 10^{-15} \ m$ $k = \frac{1}{4\pi\epsilon_0} = 9 	imes 10^9 \ N \cdot m^2/C^2$ Substituting the values: $V = (9 	imes 10^9) 	imes \frac{50 	imes 1.6 	imes 10^{-19}}{9 	imes 10^{-15}}$ $V = (9 	imes 10^9) 	imes \frac{80 	imes 10^{-19}}{9 	imes 10^{-15}}$ $V = 80 	imes 10^{9-19+15}$ $V = 80 	imes 10^5 \ V = 8 	imes 10^6 \ V$

If the radius of a nucleus with atomic number $Z = 50$ is $9 \times 10^{-15} \ m$,what is the electric potential at its surface?

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