A ball of mass 150 , g moving with a velocity | vedclass

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Question

(A) Given: Mass $m = 150 \, g = 0.15 \, kg$.Initial velocity $u = -12 \, m/s$ (taking the direction towards the bat as negative).Final velocity $v = +

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(A) Given: Mass $m = 150 \, g = 0.15 \, kg$.Initial velocity $u = -12 \, m/s$ (taking the direction towards the bat as negative).Final velocity $v = +20 \, m/s$ (taking the direction away from the bat as positive).Time interval $\Delta t = 0.01 \, s$.According to Newton's Second Law of Motion,the force $F$ is given by the rate of change of momentum:$F = \frac{m(v - u)}{\Delta t}$$F = \frac{0.15 	imes (20 - (-12))}{0.01}$$F = \frac{0.15 	imes (20 + 12)}{0.01}$$F = \frac{0.15 	imes 32}{0.01}$$F = 15 	imes 32 = 480 \, N$.Therefore,the force exerted by the bat is $480 \, N$.

$A$ ball of mass $150 \, g$ moving with a velocity of $12 \, m/s$ hits a bat and returns with a velocity of $20 \, m/s$ in the opposite direction within $0.01 \, s$. The force exerted by the bat on the ball is ........... $N$.

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