$A$ car of mass $100 \, kg$ is moving with a velocity of $5 \, m/s$. The force required to stop it in $\frac{1}{10} \, s$ is . . . . . . $N$.

$A$ body of mass $2 \ kg$ moving with velocity of $\overrightarrow{v}_{in} = 3 \hat{i} + 4 \hat{j} \ ms^{-1}$ enters into a constant force field of $6 \ N$ directed along the positive $z$-axis. If the body remains in the field for a period of $\frac{5}{3} \ s$, then the velocity of the body when it emerges from the force field is:

An army vehicle of mass $1000\, kg$ is moving with a velocity of $10\, m/s$. It is acted upon by a forward force of $1000\, N$ due to the engine and a retarding force of $500\, N$ due to friction. What will be its velocity after $10\, s$ (in $, m/s$)?

$A$ body of mass $5 \ kg$ starts from the origin with an initial velocity $(30 \hat{i} + 40 \hat{j}) \ m/s$. If a constant force $-(\hat{i} + 5 \hat{j}) \ N$ acts on the body,then the time in which the $y$-component of its velocity becomes zero is (in $s$)

$A$ particle of mass $m$ is moving in a straight line with momentum $p$. Starting at time $t = 0$,a force $F = kt$ acts in the same direction on the moving particle during time interval $T$ so that its momentum changes from $p$ to $3p$. Here $k$ is a constant. The value of $T$ is

The maximum acceleration of a $5\,kg$ block is $.............\,m/s^{2}$.