If the focus of a parabola is (3, 0) and the | vedclass

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(B) The length of the latus rectum of a parabola is given by $4a = 8$,which implies $a = 2$.Since the focus is $(3, 0)$ and the $y$-coordinate is $0$,

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$(1, 0)$

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(B) The length of the latus rectum of a parabola is given by $4a = 8$,which implies $a = 2$.Since the focus is $(3, 0)$ and the $y$-coordinate is $0$,the axis of the parabola is the $x$-axis.The standard form of such a parabola is $(y - k)^2 = 4a(x - h)$,where $(h, k)$ is the vertex.Given the focus is $(h + a, k) = (3, 0)$,we have $k = 0$ and $h + a = 3$.Substituting $a = 2$,we get $h + 2 = 3$,so $h = 1$.Therefore,the vertex $(h, k)$ is $(1, 0)$.

If the focus of a parabola is $(3, 0)$ and the length of its latus rectum is $8$,what is its vertex?

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