In the structure CH_2 = CH - C equiv CH,what | vedclass

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(A) The given structure is $CH_2 = CH - C \equiv CH$.Let us label the carbons as $C_1, C_2, C_3, C_4$ from left to right: $C_1H_2 = C_2H - C_3 \equiv

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$sp^2, sp$

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(A) The given structure is $CH_2 = CH - C \equiv CH$.Let us label the carbons as $C_1, C_2, C_3, C_4$ from left to right: $C_1H_2 = C_2H - C_3 \equiv C_4H$.The single bond is between $C_2$ and $C_3$.$C_2$ is bonded to one double bond and two single bonds (one with $C_1$,one with $H$,one with $C_3$),so it has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridization.$C_3$ is bonded to one triple bond and one single bond,so it has $2$ sigma bonds and $0$ lone pairs,resulting in $sp$ hybridization.Therefore,the hybridization states of the carbon atoms connected by the single bond are $sp^2$ and $sp$.

In the structure $CH_2 = CH - C \equiv CH$,what are the hybridization states of the carbon atoms that are connected to each other by a single bond?

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$CH_3-CH_2-CH=CH_2$ has hybridisation

In the molecule $CH_2=C=CH-CH_3$ (where the atoms are numbered $1, 2, 3,$ and $4$ respectively),the hybridization of carbon $1, 2, 3,$ and $4$ are:

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