In the molecule $CH_2=C=CH-CH_3$ (where the atoms are numbered $1, 2, 3,$ and $4$ respectively),the hybridization of carbon $1, 2, 3,$ and $4$ are:

Determine the hybridization of the $C_3$ and $C_6$ carbon atoms in the given structure,respectively. (Numbering starts from the left end of the longest chain containing the principal functional group).

The pair of electrons in the given carbanion,$CH_{3}C\equiv C^{-},$ is present in which of the following orbitals?

In which of the following compounds is the underlined carbon atom $sp^3$ hybridized?

$(a)$ Discuss the concept of hybridization. What are its different types in a carbon atom.
$(b)$ What is the type of hybridization of carbon atoms marked with a star in the following structures:
$(a)$ $\overset{*}{C}H_2 = CH - C(=O)OH$
$(b)$ $CH_3 - \overset{*}{C}H_2 - OH$
$(c)$ $CH_3 - CH_2 - \overset{*}{C}H = O$
$(d)$ $\overset{*}{C}H_3 - CH = CH - CH_3$
$(e)$ $CH_3 - \overset{*}{C} \equiv CH$

In the following molecule,the two carbon atoms marked by asterisk $(*)$ possess the following type of hybridized orbitals: $CH_3-C^* \equiv C^*-CH_3$