CH_3-CH_2-CH=CH_2 has hybridisation | vedclass

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(A) The given molecule is $CH_3-CH_2-CH=CH_2$.$1$. The first carbon $(CH_3)$ is bonded to three hydrogens and one carbon via single bonds,so it is $sp

Vedclass · Accepted Answer

$sp^3, sp^3, sp^2, sp^2$

Vedclass · Answer

(A) The given molecule is $CH_3-CH_2-CH=CH_2$.$1$. The first carbon $(CH_3)$ is bonded to three hydrogens and one carbon via single bonds,so it is $sp^3$ hybridized.$2$. The second carbon $(-CH_2-)$ is bonded to two hydrogens and two carbons via single bonds,so it is $sp^3$ hybridized.$3$. The third carbon $(-CH=)$ is bonded to one hydrogen and one carbon via a double bond,so it is $sp^2$ hybridized.$4$. The fourth carbon $(=CH_2)$ is bonded to two hydrogens via single bonds and one carbon via a double bond,so it is $sp^2$ hybridized.Thus,the hybridization sequence is $sp^3, sp^3, sp^2, sp^2$.

$CH_3-CH_2-CH=CH_2$ has hybridisation

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