Which of the following compounds is an optica | vedclass

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(C) molecule is optically active if it contains a chiral center,which is a carbon atom bonded to four different groups.Option $A$: $CH_3 - CH_2 - C \e

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(C) molecule is optically active if it contains a chiral center,which is a carbon atom bonded to four different groups.Option $A$: $CH_3 - CH_2 - C \equiv CH$ ($1$-butyne) has no chiral center.Option $B$: $CH_3 - CH_2 - CH(CH_3) - CH_3$ ($2$-methylbutane) has no chiral center.Option $C$: The structure is $1$-cyclopropyl$-1-$ethanol derivative or similar,specifically $1$-cyclopropylethane. The central carbon is bonded to $H$,$CH_3$,$C_2H_5$,and a cyclopropyl group. Since all four groups are different,the carbon is chiral,making the molecule optically active.Option $D$: $CH_3 - CH_2 - CH_2 - CH_3$ (n-butane) has no chiral center.Therefore,the correct option is $C$.

Which of the following compounds is an optically active substance with a low molecular weight?

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