The optically active molecule is

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(C) An optically active molecule must lack a plane of symmetry or a center of inversion. In option $(A)$,the molecule has a plane of symmetry,making i

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(C) An optically active molecule must lack a plane of symmetry or a center of inversion. In option $(A)$,the molecule has a plane of symmetry,making it a meso compound. In option $(B)$,the molecule has a plane of symmetry,making it a meso compound. In option $(C)$,the molecule has different functional groups at the ends ($COOMe$ and $COOH$),which prevents the existence of a plane of symmetry,thus making it optically active. In option $(D)$,the molecule has a plane of symmetry,making it a meso compound. Therefore,only molecule $(C)$ is optically active.

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