In the molecule $HC \equiv C - CH_2 - CH = CH - CH_3$,what is the type of hybridization for the $C_2 - C_3$ bond?

  • A
    $sp - sp^2$
  • B
    $sp^3 - sp^3$
  • C
    $sp - sp^3$
  • D
    $sp^2 - sp^2$

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Similar Questions

Which among the following possesses a $sp$ carbon in its structure?

Which of the following compounds do not have $sp^3$ carbon atom$(s)$?
$I$. Acetone
$II$. Acetic acid
$III$. Buta-$1,3$-diene
$IV$. Propyne
$V$. Naphthalene

In the reaction,the hybridisation states of carbon atoms $1, 2, 3, 4$ are:
$Br-CH=CH-Br \xrightarrow[Catalyst]{H_2} Br-CH_2-CH_2-Br$

The compounds containing $sp$-hybridised carbon atom are:
$(I)$ $H_3C-N(CH_3)-CHO$
$(II)$ Pyridine
$(III)$ $H_3C-CN$
$(IV)$ $H_2C=C=CH-CH_3$

From the following compounds,the ones which contain both $sp$ and $sp^2$ hybridized carbons are:

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