The compounds containing sp-hybridised carbon | vedclass

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(B) To determine the hybridisation of carbon atoms,we count the number of sigma bonds and lone pairs (if any) around the carbon atom.$(I)$ $N,N$-Dimet

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$III$ and $IV$

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(B) To determine the hybridisation of carbon atoms,we count the number of sigma bonds and lone pairs (if any) around the carbon atom.$(I)$ $N,N$-Dimethylformamide: All carbon atoms are $sp^3$ or $sp^2$ hybridised.$(II)$ Pyridine: All carbon atoms are $sp^2$ hybridised.$(III)$ Acetonitrile $(CH_3CN)$: The carbon atom in the cyano group $(-CN)$ is bonded to nitrogen by a triple bond. It has two sigma bonds and no lone pairs,so it is $sp$ hybridised.$(IV)$ Buta$-1,2-$diene $(H_2C=C=CH-CH_3)$: The central carbon atom is bonded to two other carbon atoms by double bonds. It has two sigma bonds and no lone pairs,so it is $sp$ hybridised.Thus,compounds $(III)$ and $(IV)$ contain $sp$-hybridised carbon atoms.

The compounds containing $sp$-hybridised carbon atom are:
$(I)$ $H_3C-N(CH_3)-CHO$
$(II)$ Pyridine
$(III)$ $H_3C-CN$
$(IV)$ $H_2C=C=CH-CH_3$

Similar Questions

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Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
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The compounds containing $sp$-hybridised carbon atom are:$(I)$ $H_3C-N(CH_3)-CHO$$(II)$ Pyridine$(III)$ $H_3C-CN$$(IV)$ $H_2C=C=CH-CH_3$