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(D) Let us analyze the hybridization of carbon atoms in each compound:$I$. Acetone $(CH_3COCH_3)$: Contains $sp^3$ hybridized methyl carbons.$II$. Ace

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$III, V$ only

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(D) Let us analyze the hybridization of carbon atoms in each compound:$I$. Acetone $(CH_3COCH_3)$: Contains $sp^3$ hybridized methyl carbons.$II$. Acetic acid $(CH_3COOH)$: Contains an $sp^3$ hybridized methyl carbon.$III$. Buta-$1,3$-diene $(CH_2=CH-CH=CH_2)$: All four carbon atoms are $sp^2$ hybridized. No $sp^3$ carbon.$IV$. Propyne $(CH_3-C\equiv CH)$: Contains an $sp^3$ hybridized methyl carbon.$V$. Naphthalene $(C_{10}H_8)$: All ten carbon atoms are part of the aromatic system and are $sp^2$ hybridized. No $sp^3$ carbon.Thus,compounds $III$ and $V$ do not contain any $sp^3$ hybridized carbon atoms.

Which of the following compounds do not have $sp^3$ carbon atom$(s)$?
$I$. Acetone
$II$. Acetic acid
$III$. Buta-$1,3$-diene
$IV$. Propyne
$V$. Naphthalene

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Which of the following compounds do not have $sp^3$ carbon atom$(s)$?$I$. Acetone$II$. Acetic acid$III$. Buta-$1,3$-diene$IV$. Propyne$V$. Naphthalene