The order of boiling points for the given com | vedclass

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Question

(B) The compounds are: $(I)$ Catechol (ortho-dihydroxybenzene),$(II)$ Resorcinol (meta-dihydroxybenzene),$(III)$ Hydroquinone (para-dihydroxybenzene),

Vedclass · Accepted Answer

$(IV) < (I) < (II) < (III)$

Vedclass · Answer

(B) The compounds are: $(I)$ Catechol (ortho-dihydroxybenzene),$(II)$ Resorcinol (meta-dihydroxybenzene),$(III)$ Hydroquinone (para-dihydroxybenzene),and $(IV)$ Phenol.Boiling point depends on intermolecular hydrogen bonding.$(IV)$ Phenol has only one $-OH$ group,so it has the lowest boiling point.Among the dihydroxybenzenes,$(I)$ Catechol exhibits intramolecular hydrogen bonding,which reduces the extent of intermolecular hydrogen bonding,leading to a lower boiling point compared to $(II)$ and $(III)$.$(III)$ Hydroquinone has a symmetrical structure and strong intermolecular hydrogen bonding,resulting in the highest boiling point.$(II)$ Resorcinol has an intermediate boiling point.Thus,the order is: $(IV) < (I) < (II) < (III)$.

The order of boiling points for the given compounds is:

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