Arrange the following compounds in increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $C-OH$ bond length depends on the extent of resonance (partial double bond character).In $CH_3OH$,the $C-OH$ bond is a pure single bond,so it

Vedclass · Accepted Answer

$phenol < p-$ethoxyphenol $< methanol$

Vedclass · Answer

(A) The $C-OH$ bond length depends on the extent of resonance (partial double bond character).In $CH_3OH$,the $C-OH$ bond is a pure single bond,so it has the longest bond length.In $phenol$,the lone pair on oxygen participates in resonance with the benzene ring,giving the $C-OH$ bond partial double bond character.In $p-$ethoxyphenol,the $-OEt$ group is a strong electron-donating group ($+M$ effect). This increases the electron density in the ring,which opposes the resonance of the $-OH$ group,thereby reducing the partial double bond character of the $C-OH$ bond compared to phenol.Therefore,the partial double bond character is: $phenol > p-$ethoxyphenol $> methanol$ (pure single bond).Consequently,the bond length order is: $phenol < p-$ethoxyphenol $< methanol$.

Arrange the following compounds in increasing order of $C-OH$ bond length: methanol,phenol,$p-$ethoxyphenol.

Similar Questions

The structure of salol is

An organic compound with molecular formula $C_7H_8O$ dissolves in $NaOH$ and gives a characteristic colour with $FeCl_3$. On treatment with bromine,it gives a tribromo derivative $C_7H_5OBr_3$. The compound is

The major product of the following reaction is:

What is the product formed when phenol reacts with $Br_2$ in $CCl_4$ at low temperature?

Phenol $+$ Aniline $\xrightarrow[{KOH}]{{C_6H_5N_2^+Cl^{-}}}$ Major Product $:$ Product will be $:$

Vedclass Test Series

Exam Paper Generator

Online Exam Module