What will be the product of the reaction CH_3 | vedclass

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(A) The reaction of an internal alkyne with ozone followed by hydrolysis is an oxidative cleavage reaction.For an internal alkyne $R-C \equiv C-R'$,th

Vedclass · Accepted Answer

$CH_3COOH + CH_3CH_2COOH$

Vedclass · Answer

(A) The reaction of an internal alkyne with ozone followed by hydrolysis is an oxidative cleavage reaction.For an internal alkyne $R-C \equiv C-R'$,the products are two carboxylic acids: $R-COOH$ and $R'-COOH$.In the given reaction,$CH_3-C \equiv C-CH_2CH_3$ is cleaved at the triple bond.The fragments are $CH_3-C \equiv$ and $\equiv C-CH_2CH_3$.Upon oxidation,these yield $CH_3COOH$ (acetic acid) and $CH_3CH_2COOH$ (propanoic acid).Therefore,the correct products are $CH_3COOH + CH_3CH_2COOH$.

What will be the product of the reaction $CH_3-C \equiv C-CH_2CH_3 \xrightarrow[(2) \text{ Hydrolysis}]{(1) O_3} \, ?$

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