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(A) The reaction of propyne $(CH_3-C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$

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$CH_3-C \equiv CH + 2 HBr \longrightarrow$

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(A) The reaction of propyne $(CH_3-C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ adds to the triple bond to form $2-$bromopropene $(CH_3-C(Br)=CH_2)$. In the second step,another molecule of $HBr$ adds to the double bond,again following Markovnikov's rule,to form $2,2-$dibromopropane $(CH_3-C(Br)_2-CH_3)$. Therefore,the reaction $CH_3-C \equiv CH + 2 HBr \longrightarrow CH_3-C(Br)_2-CH_3$ is the correct one.

Which reaction among the following will yield $2,2-$dibromopropane?

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