The major product in the following reaction i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of vinyl bromide $(CH_2=CHBr)$ with a strong base like $NaNH_2$ is a dehydrohalogenation reaction. $NaNH_2$ is a very strong base tha

Vedclass · Accepted Answer

$H-C \equiv C-H$

Vedclass · Answer

(A) The reaction of vinyl bromide $(CH_2=CHBr)$ with a strong base like $NaNH_2$ is a dehydrohalogenation reaction. $NaNH_2$ is a very strong base that abstracts a proton from the vinyl bromide,leading to the elimination of $HBr$ and the formation of the triple bond in acetylene $(HC \equiv CH)$. The reaction is: $CH_2=CHBr + NaNH_2 \rightarrow HC \equiv CH + NaBr + NH_3$ Thus,the major product is acetylene $(HC \equiv CH)$.

The major product in the following reaction is

Similar Questions

$1$-Alkyne and $2$-alkyne can be distinguished by

What is formed when $CH_3C \equiv CH$ reacts with $CH_3MgX$?

Addition of $HCN$ to ethyne in the presence of $Ba(CN)_2$ as a catalyst gives:

Acetylenyl hydrocarbons are acidic because ..

Choose the sequence of steps that describes the best synthesis of but$-1$-ene from ethanol.

Vedclass Test Series

Exam Paper Generator

Online Exam Module