Three forces of 3 N,4 N,and 12 N act at a | vedclass

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(B) Since the three forces are mutually perpendicular,they can be represented along the $x$,$y$,and $z$ axes as vectors $\vec{F_1} = 3\hat{i}$,$\vec{F

Vedclass · Accepted Answer

$13$

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(B) Since the three forces are mutually perpendicular,they can be represented along the $x$,$y$,and $z$ axes as vectors $\vec{F_1} = 3\hat{i}$,$\vec{F_2} = 4\hat{j}$,and $\vec{F_3} = 12\hat{k}$.The resultant force vector is $\vec{F} = 3\hat{i} + 4\hat{j} + 12\hat{k}$.The magnitude of the resultant force is given by $|\vec{F}| = \sqrt{F_x^2 + F_y^2 + F_z^2}$.Substituting the values: $|\vec{F}| = \sqrt{3^2 + 4^2 + 12^2} = \sqrt{9 + 16 + 144} = \sqrt{169}$.Therefore,the magnitude of the resultant force is $13 \ N$.

Three forces of $3 \ N$,$4 \ N$,and $12 \ N$ act at a point in mutually perpendicular directions. Find the magnitude of the resultant force in $N$.

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