(A) Let the two consecutive integers be $n$ and $n+1$.For a quadratic equation $x^2 - bx + c = 0$,the roots are $\alpha$ and $\beta$.Given $\alpha = n

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(A) Let the two consecutive integers be $n$ and $n+1$.For a quadratic equation $x^2 - bx + c = 0$,the roots are $\alpha$ and $\beta$.Given $\alpha = n$ and $\beta = n+1$.The discriminant $D = b^2 - 4c$.We know that $D = (\alpha - \beta)^2$.Substituting the values,$D = (n - (n+1))^2 = (-1)^2 = 1$.Therefore,$b^2 - 4c = 1$.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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If the roots of the equation $x^2 - bx + c = 0$ are two consecutive integers,then $b^2 - 4c = ......$

A
$1$
B
$2$
C
$3$
D
$4$

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4-2.Quadratic Equations and Inequations

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Solution of quadratic equations and Nature of roots

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If the roots of the equation $x^2 - bx + c = 0$ are two consecutive integers,then $b^2 - 4c = ......$

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