The negation of the statement "If $I$ become a teacher,then $I$ will open a school" is:
- A$I$ will not become a teacher or $I$ will open a school.
- B$I$ will become a teacher and $I$ will not open a school.
- CPerhaps $I$ will not become a teacher or $I$ will not open a school.
- DNeither $I$ will become a teacher nor $I$ will open a school.
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Similar Questions
$p$ and $q$ are two logical statements. If $r: p \rightarrow (\sim p \vee q)$ has truth value false,then the truth values of $p$ and $q$ are respectively:
The logically equivalent proposition of $p \Leftrightarrow q$ is
DifficultAIEEE 2012
View SolutionWhich of the following statements is correct?
$(a)$ $S_1: (p \wedge q) \equiv \sim(p \rightarrow \sim q)$
$(b)$ $S_2: (p \wedge q) \wedge (\sim p \vee \sim q)$ is a tautology
$(c)$ $S_3: [p \wedge (p$ $\rightarrow \sim q)]$ $\rightarrow q$ is a contradiction
$(d)$ $S_4: p$ $\rightarrow (q$ $\rightarrow p)$ is a contingency
$(a)$ $S_1: (p \wedge q) \equiv \sim(p \rightarrow \sim q)$
$(b)$ $S_2: (p \wedge q) \wedge (\sim p \vee \sim q)$ is a tautology
$(c)$ $S_3: [p \wedge (p$ $\rightarrow \sim q)]$ $\rightarrow q$ is a contradiction
$(d)$ $S_4: p$ $\rightarrow (q$ $\rightarrow p)$ is a contingency
The Boolean expression $(p \wedge \sim q) \Rightarrow (q \vee \sim p)$ is equivalent to:
The compound statement $(P \vee Q) \wedge (\sim P) \Rightarrow Q$ is equivalent to:
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