Light exhibits wave nature because...

When two light waves of equal intensity superimpose,the maximum intensity obtained is $I$. If the intensity of one of the waves is quadrupled,then the maximum intensity obtained is

The contrast in the fringes in an interference pattern depends on

Two point sources $X$ and $Y$ emit waves of the same frequency and speed,but $Y$ lags in phase behind $X$ by $2\pi l$ radians. If there is a maximum in direction $D$,the distance $XO$ (where $n$ is an integer) is given by:

Two periodic waves of intensities $I_{1}$ and $I_{2}$ pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is

The ratio of intensities of two waves producing interference is $9: 4$. The ratio of the resultant maximum and minimum intensities will be: