When two light waves of equal intensity superimpose,the maximum intensity obtained is $I$. If the intensity of one of the waves is quadrupled,then the maximum intensity obtained is

Two coherent sources whose intensity ratio is $64: 1$ produce interference fringes. The ratio of intensities of maxima and minima is

In an interference experiment,two coherent waves $S_1$ and $S_2$ are represented by $y_1 = 10 \sin(\omega t)$ and $y_2 = 10 \sin(\omega t - \pi/6)$ respectively. When these waves superimpose to form an interference pattern,the maximum intensity is ....... (Assume $K = 1$)

The light beams of intensities in the ratio of $9: 1$ are allowed to interfere. What will be the ratio of the intensities of maxima and minima?

Four light waves are represented by:
$(i)$ $y = a_1 \sin \omega t$
(ii) $y = a_2 \sin (\omega t + \phi)$
(iii) $y = a_1 \sin 2\omega t$
(iv) $y = a_2 \sin 2(\omega t + \phi)$
Interference fringes may be observed due to the superposition of:

Coherent sources are those sources for which